Now we are making a solution that has to get the package reference. But the version of package reference is a range and the default version parser need input a version but not a version range. This post will tell you how to parse the version range string to reference version.
The format for reference version is like this
[2.1.0.293,3.0)
[1.1.0.34,2.0)
(1.1.0.34,2.0]
2.1
For parse the reference version string, we should make some property.
public class ReferenceVersion
{
public ReferenceVersion(Version version)
{
Version = version;
MinVersion = version;
MaxVersion = version;
IsIncludeMaxVersion = true;
IsIncludeMinVersion = true;
}
public ReferenceVersion(Version minVersion, Version maxVersion, bool isIncludeMinVersion,
bool isIncludeMaxVersion)
{
Version = null;
MinVersion = minVersion;
MaxVersion = maxVersion;
IsIncludeMinVersion = isIncludeMinVersion;
IsIncludeMaxVersion = isIncludeMaxVersion;
}
public Version Version { get; }
public Version MinVersion { get; }
public Version MaxVersion { get; }
public bool IsIncludeMinVersion { get; }
public bool IsIncludeMaxVersion { get; }
}
I will use regex to get the string and parse the string to version.
public static ReferenceVersion Parser(string str)
{
if (_regex == null)
{
_regex = new Regex(@"([(|\[])([\d|.]*),([\d|.]*)([)|\]])", RegexOptions.Compiled);
}
var res = _regex.Match(str);
if (res.Success)
{
var isIncludeMinVersion = res.Groups[1].Value;
var minVersion = res.Groups[2].Value;
var maxVersion = res.Groups[3].Value;
var isIncludeMaxVersion = res.Groups[4].Value;
return new ReferenceVersion
(
string.IsNullOrEmpty(minVersion) ? null : Version.Parse(minVersion),
string.IsNullOrEmpty(maxVersion) ? null : Version.Parse(maxVersion),
isIncludeMinVersion.Equals("["),
isIncludeMaxVersion.Equals("]")
);
}
return new ReferenceVersion(Version.Parse(str));
}
private static Regex _regex;
We can get the reference version in the solution file and know the solution reference package.
Full code:
/// <summary>
/// 引用的版本
/// 用来转换 [2.1.0.293,3.0)、 (1.1.0.3,2.0]、 5.2 的版本
/// </summary>
public class ReferenceVersion
{
/// <summary>
/// 创建引用版本
/// </summary>
/// <param name="version">版本</param>
public ReferenceVersion(Version version)
{
Version = version;
MinVersion = version;
MaxVersion = version;
IsIncludeMaxVersion = true;
IsIncludeMinVersion = true;
}
/// <summary>
/// 创建引用版本
/// </summary>
/// <param name="minVersion">最低版本</param>
/// <param name="maxVersion">最高版本</param>
/// <param name="isIncludeMinVersion">是否包括最低版本</param>
/// <param name="isIncludeMaxVersion">是否包括最高版本</param>
public ReferenceVersion(Version minVersion, Version maxVersion, bool isIncludeMinVersion,
bool isIncludeMaxVersion)
{
Version = null;
MinVersion = minVersion;
MaxVersion = maxVersion;
IsIncludeMinVersion = isIncludeMinVersion;
IsIncludeMaxVersion = isIncludeMaxVersion;
}
/// <summary>
/// 版本
/// </summary>
public Version Version { get; }
/// <summary>
/// 最低版本
/// </summary>
public Version MinVersion { get; }
/// <summary>
/// 最高版本
/// </summary>
public Version MaxVersion { get; }
/// <summary>
/// 是否包括最低版本
/// </summary>
public bool IsIncludeMinVersion { get; }
/// <summary>
/// 是否包括最高版本
/// </summary>
public bool IsIncludeMaxVersion { get; }
/// <summary>
/// 转换版本
/// </summary>
/// <param name="str"></param>
/// <returns></returns>
public static ReferenceVersion Parser(string str)
{
if (_regex == null)
{
_regex = new Regex(@"([(|\[])([\d|.]*),([\d|.]*)([)|\]])", RegexOptions.Compiled);
}
var res = _regex.Match(str);
if (res.Success)
{
var isIncludeMinVersion = res.Groups[1].Value;
var minVersion = res.Groups[2].Value;
var maxVersion = res.Groups[3].Value;
var isIncludeMaxVersion = res.Groups[4].Value;
return new ReferenceVersion
(
string.IsNullOrEmpty(minVersion) ? null : Version.Parse(minVersion),
string.IsNullOrEmpty(maxVersion) ? null : Version.Parse(maxVersion),
isIncludeMinVersion.Equals("["),
isIncludeMaxVersion.Equals("]")
);
}
return new ReferenceVersion(Version.Parse(str));
}
private static Regex _regex;
}
本文会经常更新,请阅读原文: https://dotnet-campus.github.io//post/How-to-parse-version-range.html ,以避免陈旧错误知识的误导,同时有更好的阅读体验。
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